(x^2-8x+16)/(2x-8)

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Solution for (x^2-8x+16)/(2x-8) equation: 


D( x )

2*x-8 = 0

2*x-8 = 0

2*x-8 = 0

2*x-8 = 0 // + 8

2*x = 8 // : 2

x = 8/2

x = 4

x in (-oo:4) U (4:+oo)

(x^2-(8*x)+16)/(2*x-8) = 0

(x^2-8*x+16)/(2*x-8) = 0

x^2-8*x+16 = 0

x^2-8*x+16 = 0

DELTA = (-8)^2-(1*4*16)

DELTA = 0

x = 8/(1*2)

x = 4 or x = 4

(x-4)^2 = 0

((x-4)^2)/(2*x-8) = 0

x-4 = 0 // + 4

x = 4

x in { 4} 

x belongs to the empty set

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